ProblemWe are required to write a JavaScript function that takes in two strings. The first string specifies the user name and second the owner name.If the user and owner are the same our function should return ‘hello master’, otherwise our function should return ‘hello’ appended with the name of that user.ExampleFollowing is the code − Live Democonst name = 'arnav'; const owner = 'vijay'; function greet (name, owner) {    if (name === owner){       return 'Hello master';    }    return `Hello ${name}`; }; console.log(greet(name, owner));OutputHello arnav

ProblemWe are required to write a JavaScript function that takes in an array of numbers of length at least three.Our function should simply return the third smallest number from the array.ExampleFollowing is the code − Live Democonst arr = [6, 7, 3, 8, 2, 9, 4, 5]; const thirdSmallest = () => {    const copy = arr.slice();    for(let i = 0; i < 2; i++){       const minIndex = copy.indexOf(Math.min(...copy));       copy.splice(minIndex, 1);    };    return Math.min(...copy); }; console.log(thirdSmallest(arr));Output4

ProblemWe are required to write a JavaScript function that takes in a string that contains only ‘A’, ‘B’ and ‘C’. Our function should find the minimum number of characters needed to be removed from the string so that the characters in each pair of adjacent characters are different.ExampleFollowing is the code − Live Democonst str = "ABBABCCABAA"; const removeLetters = (str = '') => {    const arr = str.split('')    let count = 0    for (let i = 0; i < arr.length; i++) {       if (arr[i] === arr[i + 1]) {          count += 1          arr.splice(i, 1)          i -= 1       }    }    return count } console.log(removeLetters(str));Output3

ProblemWe are required to write a JavaScript function that takes in a string of English alphabets.Our function should count the number of rings present in the string.O', 'b', 'p', 'e', 'A', etc. all have one rings whereas 'B' has 2ExampleFollowing is the code − Live Democonst str = 'some random text string'; function countRings(str){    const rings = ['A', 'D', 'O', 'P', 'Q', 'R', 'a', 'b', 'd', 'e', 'g', 'o', 'p', 'q'];    const twoRings = ['B'];    let score = 0;    str.split('').map(x => rings.includes(x)    ? score++    : twoRings.includes(x)    ? score = score + 2    : x    );    return score; } console.log(countRings(str));Output7

ProblemWe are required to write a JavaScript function that takes in one positive three-digit integer and rearranges its digits to get the maximum possible number.ExampleFollowing is the code − Live Democonst num = 149; const maxRedigit = function(num) {    if(num < 100 || num > 999)       return null    return +num    .toString()    .split('')    .sort((a, b) => b - a)    .join('') }; console.log(maxRedigit(num));Output941

ProblemWe are required to write a JavaScript function that takes in an array of strings. Our function should create combinations by combining all possible n consecutive strings in the array and return the longest such string that comes first.ExampleFollowing is the code − Live Democonst arr = ["zone", "abigail", "theta", "form", "libe", "zas", "theta", "abigail"]; const num = 2; function longestConsec(strarr, k) {    if (strarr.length == 0 || k > strarr.length || k longStr.length ){          longStr = newStr.join('');       }    }    return longStr; } console.log(longestConsec(arr, num));Outputabigailtheta

ProblemTwo words can mesh together if the ending substring of the first is the starting substring of the second. For instance, robinhood and hoodie can mesh together.We are required to write a JavaScript function that takes in an array of strings. If all the words in the given array mesh together, then our function should return the meshed letters in a string, otherwise we should return an empty string.ExampleFollowing is the code − Live Democonst arr = ["allow", "lowering", "ringmaster", "terror"]; const meshArray = (arr = []) => {    let res = "";    for(let i = 0; i < ... Read More

ProblemWe are required to write a JavaScript function that takes in an array of numbers, arr. Our function should return the largest difference in indexes j - i such that arr[i] {    const { length: len } = arr;    let res = 0;    for(let i = 0; i < len; i++){       for(let j = i + 1; j < len; j++){          if(arr[i] res){             res = j - i;          };       };    };    return res; }; console.log(findLargestDifference(arr));OutputAnd the output in the console will be −3

ProblemWe are required to write a JavaScript function that takes in two arrays arr1 and arr2.arr2 is a shuffled duplicate of arr1 with just one element missing.Our function should find and return that one element.ExampleFollowing is the code − Live Democonst arr1 = [6, 1, 3, 6, 8, 2]; const arr2 = [3, 6, 6, 1, 2]; const findMissing = (arr1 = [], arr2 = []) => {    const obj = {};    for (let i = 0; i < arr1.length; i++) {       if (obj[arr1[i]] === undefined) {          obj[arr1[i]] = 1;     ... Read More

ProblemWe are required to write a JavaScript function that takes in a number n. Our function should return an array showing all the ways of balancing n parenthesis.For example, for n = 3, the output will be −["()()()","(())()","()(())","(()())","((()))"]ExampleFollowing is the code − Live Democonst res = []; const buildcombination = (left, right, str) => {    if (left === 0 && right === 0) {       res.push(str);    }    if (left > 0) {       buildcombination(left-1, right+1, str+"(");    }    if (right > 0) {       buildcombination(left, right-1, str+")");    } } buildcombination(3, 0, ""); console.log(res);OutputFollowing is the console output −[ '((()))', '(()())', '(())()', '()(())', '()()()' ]