To store Unicode in a char variable, simply create a char variable.char c;Now assign unicode.char c = '\u00AB';The following is the complete example that shows what will get displayed: when Unicode is stored in a char variable and displayed.Example Live Demopublic class Demo {    public static void main(String []args) {       int a = 79;       System.out.println(a);       char b = (char) a;       System.out.println(b);       char c = '\u00AB';       System.out.println(c);    } }Output79 O «

Use the valueOf() method in Java to copy char array to string. You can also use the copyValueOf() method, which represents the character sequence in the array specified. Here, you can specify the part of array to be copied.Let us first create a character array.char[] arr = { 'p', 'q', 'r', 's' };The method valueOf() will convert the entire array into a string.String str = String.valueOf(arr);The following is an example.Example Live Demopublic class Demo {    public static void main(String []args) {       char[] arr = { 'p', 'q', 'r', 's' };       String str = String.valueOf(arr); ... Read More

To convert ASCII to string, use the toString() method. Using this method will return the associated character.Let’s say we have the following int value, which works as ASCII for us.int asciiVal = 89;Now, use the toString() method.String str = new Character((char) asciiVal).toString();Example Live Demopublic class Demo {    public static void main(String []args) {       int asciiVal = 87;       String str = new Character((char) asciiVal).toString();       System.out.println(str);    } }OutputW

To check whether the entered character is a digit, whitespace, lowercase or uppercase, you need to check for the ASCII values.Let’s say we have a value in variable “val”, which is to be checked.For Lower Case.if(val >= 97 && val = 65 && val = 48 && val = 97 && val = 65 && val = 48 && val = 97 && val = 65 && val = 48 && val

To check whether the entered value is whitespace or not in Java, use the Character.isWhitespace() method.We have a value to be checked.char val = ' ';Now let us use the Character.isWhitespace() method.if (Character.isWhitespace(val)) {    System.out.println("Value is a Whitespace!"); } else {    System.out.println("Value is not a Whitespace"); }Let us see the complete example now to check whether the entered value is whitespace or not in Java.Example Live Demopublic class Demo {    public static void main(String []args) {       char val =' ';       System.out.println("Value: "+val);       if (Character.isWhitespace(val)) {         ... Read More

The isLetterOrDigit() method in Java returns TRUE if the entered value is a letter or digit.We have the following character.char val ='P';Now, let us check for letter or digit using if-else decision-making statement.if (Character.isLetterOrDigit(val)) {    System.out.println("Value is a letter or digit!"); } else {    System.out.println("Value is neither a letter nor a digit!"); }The following is an example.Example Live Demopublic class Demo {    public static void main(String []args) {       char val ='P';       System.out.println("Value: "+val);       if (Character.isLetterOrDigit(val)) {          System.out.println("Value is a letter or digit!");       ... Read More

Let’s say we have the following string, that has some letters and numbers.String str = "9as78";Now loop through the length of this string and use the Character.isLetter() method. Within that, use the charAt() method to check for each character/ number in the string.for (int i = 0; i < str.length(); i++) {    if (Character.isLetter(str.charAt(i)))    count++; }We have set a count variable above to get the length of the letters in the string.Here’s the complete example.Example Live Demopublic class Demo {    public static void main(String []args) {       String str = "9as78";       int count ... Read More

To check whether the entered value is a letter or not in Java, use the Character.isLetter() method.We have a value to be checked.char val = 'D';Now let us use the Character.isLetter() method.if (Character.isLetter(val)) {    System.out.println("Character is in Lowercase!"); }else {    System.out.println("Character is in Uppercase!"); }Let us see the complete example now to check for letter.Example Live Demopublic class Demo {    public static void main(String []args) {       System.out.println("Checking whether the given value is a Letter or not...");       char val = 'D';       System.out.println("Value: "+val);       if (Character.isLetter(val)) {   ... Read More

To validate if a String has only numbers, you can try the following codes. We have used the matches() method in Java here to check for number in a string.Example Live Demopublic class Demo {    public static void main(String []args) {       String str = "978";       System.out.println("Checking for string that has only numbers...");       System.out.println("String: "+str);       if(str.matches("[0-9]+") && str.length() > 2)       System.out.println("String has only numbers!");       else       System.out.println("String consist of characters as well!");    } }OutputChecking for string that has only numbers... ... Read More

To check for Integer overflow, we need to check the Integer.MAX_VALUE with the subtracted integers result, Here, Integer.MAX_VALUE is the maximum value of an integer in Java.Let us see an example wherein integers are subtracted and if the result is more than Integer.MAX_VALUE, then an exception is thrown.The following is an example showing how to check for Integer overflow.Example Live Demopublic class Demo {    public static void main(String[] args) {       int val1 = 9898999;       int val2 = 8784556;       System.out.println("Value1: "+val1);       System.out.println("Value2: "+val2);       long sub = ... Read More