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Found 1349 Articles for MongoDB
350 Views
We have the following date −01-10-2019To change the date format, let us use custom variable and convert date to a string and change its format −Following is the query to implement date to string −> var inputDate="01-10-2019"; > var formatDate= inputDate.split(/-|\//); > var outputString= formatDate[2]+'-'+formatDate[0]+'-'+formatDate[1];Displaying the variable value −> print(outputString);This will produce the following output −2019-01-10
455 Views
To find if element exists in a MongoDB document, use MongoDB $exists. Let us create a collection with documents −> db.demo497.insertOne({"details":[{"Name":"Chris"}, {"Name":"Bob"}]});{ "acknowledged" : true, "insertedId" : ObjectId("5e84b3cfb0f3fa88e22790d1") } > db.demo497.insertOne({"details":[{"Name":"Carol"}]});{ "acknowledged" : true, "insertedId" : ObjectId("5e84b3d9b0f3fa88e22790d2") } > db.demo497.insertOne({"details":[{}]});{ "acknowledged" : true, "insertedId" : ObjectId("5e84b3e9b0f3fa88e22790d3") }Display all documents from a collection with the help of find() method −> db.demo497.find();This will produce the following output −{ "_id" : ObjectId("5e84b3cfb0f3fa88e22790d1"), "details" : [ { "Name" : "Chris" }, { "Name" : "Bob" } ] } { "_id" : ObjectId("5e84b3d9b0f3fa88e22790d2"), "details" : [ { "Name" : ... Read More
280 Views
For this, use the forEach(). To display the values, use printjson(). Let us create a collection with documents −> db.demo496.insertOne({"Name":"David", "CountryName":"US"});{ "acknowledged" : true, "insertedId" : ObjectId("5e84b04ab0f3fa88e22790ce") } > db.demo496.insertOne({"Name":"John", "CountryName":"AUS"});{ "acknowledged" : true, "insertedId" : ObjectId("5e84b054b0f3fa88e22790cf") } > db.demo496.insertOne({"Name":"Robert", "CountryName":"UK"});{ "acknowledged" : true, "insertedId" : ObjectId("5e84b05db0f3fa88e22790d0") }Display all documents from a collection with the help of find() method −> db.demo496.find();This will produce the following output −{ "_id" : ObjectId("5e84b04ab0f3fa88e22790ce"), "Name" : "David", "CountryName" : "US" } { "_id" : ObjectId("5e84b054b0f3fa88e22790cf"), "Name" : "John", "CountryName" : "AUS" } { "_id" : ObjectId("5e84b05db0f3fa88e22790d0"), "Name" : ... Read More
172 Views
To update only a single document, you need to update a specific data with updateOne(). The updateOne() is used to update a single document within the collection based on the filter.Let us create a collection with documents −> db.demo495.insertOne({"FirstName":"Chris", "Age":19});{ "acknowledged" : true, "insertedId" : ObjectId("5e84adfeb0f3fa88e22790ca") } > db.demo495.insertOne({"FirstName":"David", "Age":21});{ "acknowledged" : true, "insertedId" : ObjectId("5e84ae05b0f3fa88e22790cb") } > db.demo495.insertOne({"FirstName":"Bob", "Age":26});{ "acknowledged" : true, "insertedId" : ObjectId("5e84ae0eb0f3fa88e22790cc") } > db.demo495.insertOne({"FirstName":"John", "Age":22});{ "acknowledged" : true, "insertedId" : ObjectId("5e84ae15b0f3fa88e22790cd") }Display all documents from a collection with the help of find() method −> db.demo495.find();This will produce ... Read More
1K+ Views
To update elements inside an array, use $set in MongoDB. Let us create a collection with documents −> db.demo494.insertOne( ... { ... ... "CollegeDetails" : [ ... { ... "CollegeName" : "MIT", ... "Fees" : 80000 ... }, ... { ... "CollegeName" : "SU", ... "Fees" : 90000 ... } ... ] ... } ... ) { "acknowledged" : true, "insertedId" : ObjectId("5e84a5c1b0f3fa88e22790c9") }Display all documents from a ... Read More
673 Views
To count unique items in array-based fields, use $group along with aggregate(). Let us create a collection with documents −> db.demo493.insertOne({"SubjectName":["MySQL", "MongoDB", "Java"]});{ "acknowledged" : true, "insertedId" : ObjectId("5e849f97b0f3fa88e22790c4") } > db.demo493.insertOne({"SubjectName":["C++", "MongoDB", "C"]});{ "acknowledged" : true, "insertedId" : ObjectId("5e849fa4b0f3fa88e22790c5") } > db.demo493.insertOne({"SubjectName":["MySQL", "MongoDB", "C"]});{ "acknowledged" : true, "insertedId" : ObjectId("5e849fb2b0f3fa88e22790c6") }Display all documents from a collection with the help of find() method −> db.demo493.find();This will produce the following output −{ "_id" : ObjectId("5e849f97b0f3fa88e22790c4"), "SubjectName" : [ "MySQL", "MongoDB", "Java" ] } { "_id" : ObjectId("5e849fa4b0f3fa88e22790c5"), "SubjectName" : [ "C++", "MongoDB", "C" ] } ... Read More
358 Views
For nested queries, let us first create a collection with documents −> db.demo492.insertOne({ ... "ProductDetails" : ... { ... "StockDetails" : [ ... { "ProductName" : "Product-1" }, ... {"ProductName" : "Product-2"}, ... { "ProductName" : "Product-3"} ... ... ] ... ... } ... }); { "acknowledged" : true, "insertedId" : ObjectId("5e849db8b0f3fa88e22790c2") } > > > > db.demo492.insertOne({ ... "ProductDetails" : ... { ... "StockDetails" : [ ... ... Read More
3K+ Views
To match date, use $match along with aggregate(). Let us create a collection with documents −> db.demo491.insertOne({"ShippingDate":new ISODate("2020-01-10")});{ "acknowledged" : true, "insertedId" : ObjectId("5e849a09b0f3fa88e22790be") } > db.demo491.insertOne({"ShippingDate":new ISODate("2020-02-21")});{ "acknowledged" : true, "insertedId" : ObjectId("5e849a0eb0f3fa88e22790bf") } > db.demo491.insertOne({"ShippingDate":new ISODate("2020-03-23")});{ "acknowledged" : true, "insertedId" : ObjectId("5e849a1db0f3fa88e22790c0") } > db.demo491.insertOne({"ShippingDate":new ISODate()});{ "acknowledged" : true, "insertedId" : ObjectId("5e849a28b0f3fa88e22790c1") }Display all documents from a collection with the help of find() method −> db.demo491.find();This will produce the following output −{ "_id" : ObjectId("5e849a09b0f3fa88e22790be"), "ShippingDate" : ISODate("2020-01- 10T00:00:00Z") } { "_id" : ObjectId("5e849a0eb0f3fa88e22790bf"), "ShippingDate" : ISODate("2020-02- 21T00:00:00Z") } { ... Read More
221 Views
For random value with Map Reduce, use mapReduce() concept along with Math.random(). Let us create a collection with documents −> db.demo651.insertOne({Value:10}); { "acknowledged" : true, "insertedId" : ObjectId("5e9f0330e3c3cd0dcff36a57") } > db.demo651.insertOne({Value:20}); { "acknowledged" : true, "insertedId" : ObjectId("5e9f0332e3c3cd0dcff36a58") } > db.demo651.insertOne({Value:30}); { "acknowledged" : true, "insertedId" : ObjectId("5e9f0335e3c3cd0dcff36a59") } > db.demo651.insertOne({Value:40}); { "acknowledged" : true, "insertedId" : ObjectId("5e9f0337e3c3cd0dcff36a5a") } > db.demo651.insertOne({Value:50}); { "acknowledged" : true, "insertedId" : ObjectId("5e9f0339e3c3cd0dcff36a5b") } > db.demo651.insertOne({Value:60}); { "acknowledged" : true, "insertedId" : ObjectId("5e9f033be3c3cd0dcff36a5c") } > db.demo651.insertOne({Value:70}); { "acknowledged" : true, "insertedId" ... Read More
745 Views
To query only the field name, set fieldName to 0 i.e. the fieldName to hide. Let us create a collection with documents −> db.demo650.insertOne({_id:101, details:{Name:"Chris", Age:21}}); { "acknowledged" : true, "insertedId" : 101 } > db.demo650.insertOne({_id:102, details:{Name:"Bob", Age:22}}); { "acknowledged" : true, "insertedId" : 102 } > db.demo650.insertOne({_id:103, details:{Name:"Sam", Age:20}}); { "acknowledged" : true, "insertedId" : 103 } > db.demo650.insertOne({_id:104, details:{Name:"Robert", Age:24}}); { "acknowledged" : true, "insertedId" : 104 }Display all documents from a collection with the help of find() method −> db.demo650.find();This will produce the following output −{ "_id" : 101, "details" : { "Name" : "Chris", "Age" : ... Read More