You can use $facet operator for this. To understand the concept, let us create a collection with document. The query to create a collection with document is as follows −> db.totalDocumentDemo.insertOne({"InstructorId":100, "InstructorName":"Larry", "InstructorFav ouriteSubject":["Java", "MongoDB", "Python"]}); {    "acknowledged" : true,    "insertedId" : ObjectId("5c76e6701e9c5dd6f1f78274") } > db.totalDocumentDemo.insertOne({"InstructorId":200, "InstructorName":"Sam", "InstructorFav ouriteSubject":["SQL Server", "C#", "Javascript"]}); {    "acknowledged" : true,    "insertedId" : ObjectId("5c76e69c1e9c5dd6f1f78275") }Display all documents from a collection with the help of find() method. The query is as follows −> db.totalDocumentDemo.find().pretty();Output{    "_id" : ObjectId("5c76e6701e9c5dd6f1f78274"),    "InstructorId" : 100,    "InstructorName" : "Larry",    "InstructorFavouriteSubject" : [     ... Read More

To perform Regex search on integer value, you need to use $where operator. The syntax is as follows:db.yourCollectionName.find({ $where: "/^yourIntegerPatternValue.*/.test(this.yourFieldName)" });To understand the above concept, let us create a collection with document. The query to create a collection with document is as follows:> db.regExpOnIntegerDemo.insertOne({"StudentId":2341234}); {    "acknowledged" : true,    "insertedId" : ObjectId("5c70370c75eb1743ddddce21") } > db.regExpOnIntegerDemo.insertOne({"StudentId":123234}); {    "acknowledged" : true,    "insertedId" : ObjectId("5c70371175eb1743ddddce22") } > db.regExpOnIntegerDemo.insertOne({"StudentId":9871234}); {    "acknowledged" : true,    "insertedId" : ObjectId("5c70371875eb1743ddddce23") } > db.regExpOnIntegerDemo.insertOne({"StudentId":2345612}); {    "acknowledged" : true,    "insertedId" : ObjectId("5c70372275eb1743ddddce24") } > db.regExpOnIntegerDemo.insertOne({"StudentId":1239812345}); {    "acknowledged" : true,    "insertedId" : ... Read More

You can achieve this with the help of aggregate framework in MongoDB. To understand it, let us create a collection with document. The query to create a collection with document is as follows:> db.sortInnerArrayDemo.insertOne( ... ...    { ...       "EmployeeDetails": ...       { ...          "EmployeeAddress": ...          { ...             "EmployeeCountry": ...             [ ...                { ...                   "EmployeeZipCode":1003, ...       ... Read More

You can use the $size operator for internal array size in MongoDB. The syntax is as follows:db.internalArraySizeDemo.aggregate(    [       {          $group: {             _id:yourObjectIdValue,             anyFieldName: {$first: {$size: "$yourArrayName" }}          }       }    ] );To understand the above syntax, let us create a collection with some documents. The query to create a collection with documents are as follows:>db.internalArraySizeDemo.insertOne({"EmployeeName":"Mike", "EmployeeTechnology":["Jav a Web Development", "Python Web Development"]}); {    "acknowledged" : true,    "insertedId" : ObjectId("5c6eff586fd07954a48906b2") } > ... Read More

To add new field to every document in a MongoDB collection, you can use $set operator. The syntax is as follows:db.yourCollectionName.update({}, { $set: {"yourFieldName": yourValue} }, false, true);To understand the above syntax, let us create a collection with some documents. The query to create a collection with documents is as follows:>db.addNewFieldToEveryDocument.insertOne({"StudentName":"John", "StudentAddress":"US "}); {    "acknowledged" : true,    "insertedId" : ObjectId("5c6efc0b6fd07954a48906ae") } >db.addNewFieldToEveryDocument.insertOne({"StudentName":"David", "StudentAddress":"U K"}); {    "acknowledged" : true,    "insertedId" : ObjectId("5c6efc0b6fd07954a48906af") } >db.addNewFieldToEveryDocument.insertOne({"StudentName":"Carol", "StudentAddress":"U K"}); {    "acknowledged" : true,    "insertedId" : ObjectId("5c6efc0b6fd07954a48906b0") } >db.addNewFieldToEveryDocument.insertOne({"StudentName":"Bob", "StudentAddress":"US" }); {    "acknowledged" : true,    "insertedId" : ... Read More

You can use $unset operator to remove a field completely from a MongoDb document. The syntax is as follows:db.yourCollectionName.update({}, {$unset: {yourFieldName:1}}, false, true);To understand the above syntax, let us create a collection with some documents. The query to create a collection with documents are as follows:> db.removeFieldCompletlyDemo.insertOne({"StudentName":"Larry", "StudentFavouriteSubject": ["Java", "C", "C++", "Python"]}); {    "acknowledged" : true,    "insertedId" : ObjectId("5c6ef55a6fd07954a48906a3") } > db.removeFieldCompletlyDemo.insertOne({"StudentName":"Mike", "StudentFavouriteSubject": ["Javascript", "HTML5", "CSS3"]}); {    "acknowledged" : true,    "insertedId" : ObjectId("5c6ef57b6fd07954a48906a4") } > db.removeFieldCompletlyDemo.insertOne({"StudentName":"Sam", "StudentFavouriteSubject": ["MongoDB", "MySQL", "SQL Server"]}); {    "acknowledged" : true,    "insertedId" : ObjectId("5c6ef59c6fd07954a48906a5") }Display all documents from a collection ... Read More

To convert the string to date in MongoDB, use the following syntax:db.yourCollectionName.aggregate(    [       {          $project:          {             anyVariableName:             {                $dateFromString:                {                   dateString: '$yourFieldName’                }             }          }       }    ] );To understand the above syntax, ... Read More

You can use aggregate framework to group by dates in MongoDB. Let us first create a collection with some documents. The query to create a collection with documents are as follows:> db.groupByDateDemo.insertOne({"UserLoginDateTime":new ISODate()}); {    "acknowledged" : true,    "insertedId" : ObjectId("5c6ee4df6fd07954a4890695") } > db.groupByDateDemo.insertOne({"UserLoginDateTime":new ISODate("2019-01-31 15:20:09.234Z")}); {    "acknowledged" : true,    "insertedId" : ObjectId("5c6ee51c6fd07954a4890696") } > db.groupByDateDemo.insertOne({"UserLoginDateTime":new ISODate("2017-04-21 16:12:13.240Z")}); {    "acknowledged" : true,    "insertedId" : ObjectId("5c6ee5336fd07954a4890697") } > db.groupByDateDemo.insertOne({"UserLoginDateTime":new ISODate("2016-05-25 19:11:21.130Z")}); {    "acknowledged" : true,    "insertedId" : ObjectId("5c6ee54b6fd07954a4890698") } > db.groupByDateDemo.insertOne({"UserLoginDateTime":new ISODate("2016-05-25 19:11:21.130Z")}); {    "acknowledged" : true,    "insertedId" : ObjectId("5c6ee8de6fd07954a4890699") } > ... Read More

Let us convert string type to int for an example. Aggregation does not allow us to directly change the type of a field; therefore, you need to write a code to convert the type of a field.At first, create a collection with document. After that we will get the type of every field. The query to create a collection with document is as follows>db.changeDataType.insertOne({"StudentName":"Larry", "StudentAge":23, "StudentZipCode":" 10001", "isProgrammer":false}); {    "acknowledged" : true,    "insertedId" : ObjectId("5c6ed4976fd07954a4890694") }Display all documents from a collection with the help of find() method. The query is as follows:> db.changeDataType.find().pretty();The following is the output:{   ... Read More

To get the last N records in MongoDB, you need to use limit(). The syntax is as follows:db.yourCollectionName.find().sort({$natural:-1}).limit(yourValue);To understand the above syntax, let us create a collection with document. The query to create a collection with document is as follows:> db.getLastNRecordsDemo.insertOne({"EmployeeName":"Maxwell"}); {    "acknowledged" : true,    "insertedId" : ObjectId("5c6ecf3d6fd07954a4890689") } > db.getLastNRecordsDemo.insertOne({"EmployeeName":"Carol"}); {    "acknowledged" : true,    "insertedId" : ObjectId("5c6ecf496fd07954a489068a") } > db.getLastNRecordsDemo.insertOne({"EmployeeName":"Bob"}); { "acknowledged" : true,    "insertedId" : ObjectId("5c6ecf4e6fd07954a489068b") } > db.getLastNRecordsDemo.insertOne({"EmployeeName":"Sam"}); {    "acknowledged" : true,    "insertedId" : ObjectId("5c6ecf546fd07954a489068c") } > db.getLastNRecordsDemo.insertOne({"EmployeeName":"Robert"}); {    "acknowledged" : true,    "insertedId" : ObjectId("5c6ecf596fd07954a489068d") } > db.getLastNRecordsDemo.insertOne({"EmployeeName":"Mike"}); ... Read More