In this program we will see how to search an element in an array of bytes using 8085.Problem StatementWrite 8085 Assembly language program to search a key value in an array of data using linear search technique.DiscussionIn this program the data are stored at location 8002H to 8007H. The 8000H is containing the size of the block, and 8001H is holding the key value to search. After executing this program, it will return the address of the data where the item is found and store the address at location 9000H and9001H. If the item is not found, it will return ... Read More

Now let us see a program of Intel 8085 Microprocessor. This program will convert binary or hexadecimal number to ASCII values.Problem StatementWrite 8085 Assembly language program to convert binary or Hexadecimal characters to ASCII values. DiscussionWe know that the ASCII of number 00H is 30H (48D), and ASCII of 09H is39H (57D). So all other numbers are in the range 30H to 39H. TheASCII value of 0AH is 41H (65D) and ASCII of 0FH is 46H (70D), so all other alphabets (B, C, D, E, F) are in the range 41H to 46H.Here we are providing hexadecimal digit at memory location ... Read More

Now let us see a program of Intel 8085 Microprocessor. This program will convert 8-bit BCDnumbers to two digit ASCII values.Problem StatementWrite 8085 Assembly language program where an 8-bit BCD number is stored in memory location 8050H. Separate each BCD digit and convert it to corresponding ASCII code and store it to the memory location 8060H and 8061H.DiscussionIn this problem we are using a subroutine to convert one BCD digit(nibble) to its equivalent ASCII values. As the 8-bit BCD number contains two nibbles, so we can execute this subroutine to find ASCIIvalues of them. We can get the lower nibble ... Read More

Now let us see a program of Intel 8085 Microprocessor. This program will convert gray code to binary code.Problem StatementWrite an assembly language program for 8085 to convert gray code to binary code. The data is stored at address 8200H & store the result at memory location 8201H.DiscussionHere we are loading the number from memory and in each step we are performing right shift, and XOR the intermediate result with the previous one. Thus we are getting the result. In the following demonstration you can get the logic.C       1110 1011    (A) (EBH) 07H     0111 ... Read More

In this program we will see how to find the gray code from an 8-bit number.Problem StatementWrite 8085 Assembly language program to convert an 8-bit number stored at 8000H to its equivalent gray code. The result will be stored at 8050H.DiscussionIn this program we are converting binary to gray code. The procedure is simple. At first we have to shift the content to the right, then perform XOR operation with the sifted content and the actual content. Thus we will get the gray code. For an example if the number is ABH, then the binary value will be (1010 1011), ... Read More

In this program we will see how to find the gray code from an 8-bit number.Problem StatementWrite 8085 Assembly language program to convert an 8-bit number stored at 8000H to its equivalent gray code. The result will be stored at 8050H.DiscussionIn this program we are converting binary to gray code. The procedure is simple. At first we have to shift the content to the right, then perform XOR operation with the sifted content and the actual content. Thus we will get the gray code. For an example if the number is ABH, then the binary value will be (1010 1011), ... Read More

In this program we will see how to add a blocks of data using 8085 microprocessor.Problem StatementWrite 8085 Assembly language program to add numbers in an array, where the size of the array is N. The value of N is provided.DiscussionIn this problem we are using location 8000H to hold the length of the block. The main block is stored from address 8010H. We are storing the result at location 9000H and 9001H. The 9000H holding the lower byte, and 9001H is holding the upper byte.Repeatedly we are taking the number from the memory, then adding it with accumulator and ... Read More

Now let us see a program of Intel 8085 Microprocessor. This program will find the square root of a number.Problem StatementWrite an assembly language program to find the square root of a number in L and store the result at location 8100HDiscussionHere we are using division method for finding square root of a number. As we know there is no division operation in 8085, so we are creating division subroutine.Let N is the number.X = √NX2 = NX2 + X2 = N + X22X2 = N + X2X2 = (N + X2)/2X =((N + X2)/X)/2XNew=(N / X + X)/2If X ... Read More

In this program we will see how to add a blocks of data using 8085 microprocessor.Problem StatementWrite 8085 Assembly language program to add N 1-byte numbers. The value of N is provided.DiscussionIn this problem we are using location 8000H to hold the length of the block. The main block is stored from address 8010H. We are storing the result at location 9000H and 9001H. The 9000H holding the lower byte, and 9001H is holding the upper byte.Repeatedly we are taking the number from the memory, then adding it with accumulator and increase the register E content when carry flag is ... Read More

In this program we will see how to multiply two 8-bit numbers using 8085 microprocessor.Problem StatementWrite 8085 Assembly language program to multiply two 8-bit numbers stored in memory location and store the 16-bit results into the memory.DiscussionThe 8085 has no multiplication operation. To get the result of multiplication, we should use the repetitive addition method.After multiplying two 8-bit numbers it may generate 1-byte or 2-byte numbers, so we are using two registers to hold the result.We are saving the data at location 8000H and 8001H. The result is storing at location 8050H and 8051H.InputAddressData......8000DC8001AC......Flow DiagramProgramAddressHEX CodesLabelsMnemonicsCommentsF00021, 00, 80LXI H, 8000HLoad ... Read More