Given with an array of elements and the task is to print those numbers whose digit sum is also prime and return -1 is not such digit exists in an arrayInput: arr[]={2, 4, 3, 19, 25, 6, 11, 12, 18, 7} Output : 2, 3, 25, 11, 12, 7Here, the given output is generated as it contains those additive numbers whose sum is also prime like − 2, 3, 7 are prime but 25(2+5=7), 11(1+1=2), 12(1+2=3) are also prime whereas numbers like 19(1+9=10) are not prime.AlgorithmSTART Step 1 -> Take array of int with values Step 2 -> declare start ... Read More

Here, the task is to print those number in an array having 1, 2 and 3 as digits in their numbers and if their is no such number than the output must be -1Input : arr[] = {320, 123, 124, 125, 14532, 126, 340, 123400, 100032, 13, 32, 3123, 1100} Output : 123 3123 14532 100032 123400 Since the array have values with digits 1, 2 and 3 it wouldn’t return -1 and print 5 values that Contain 1, 2 and 3 in their respective numbers.AlgorithmSTART Step 1 -> Declare array with elements of int type as arr Step ... Read More

Given a 2d array of n*n and the task is to find the antispiral arrangement of the given matrixInput : arr[4][4]={1,2,3,4,    5,6,7,8,    9,10,11,12    13,14,15,16} Output : 1 6 11 16 4 7 10 13AlgorithmSTART Step 1 -> declare start variables as r=4, c=4, i and j Step 2 -> initialize array as mat[r][c] with elements Step 3 -> Loop For i=0 and i print Step 5 -> Loop For i=0 and i

Given a 2d array of n*n and the task is to find the antispiral arrangement of the given matrixInput : arr[4][4]={1,2,3,4,    5,6,7,8,    9,10,11,12    13,14,15,16} Output: 10 11 7 6 5 9 13 14 15 16 12 8 4 3 2 1For this, stack can be used where the transpose of a matrix can be pushed inside stack and poped reverselyAlgorithmSTART STEP 1 -> declare stack vector element as stk and variables as int r=4, c=4, i, j, rs=0 and cs=0 Step 2 -> store matrix elements in 2-3 array Step 3 -> Loop For i=0 and o

Given with an array of int elements, the task is to arrange the elements in descending order and finding their occurrences.Input : arr[]={1, 1, 1, 2, 2, 2, 3, 3, 4, 5, 6, 7, 7} Output : 7 occurs: 2    6 occurs: 1    5 occurs: 1    4 occurs: 1    3 occurs: 2    2 occurs: 3    1 occurs: 3AlgorithmSTART Step 1 -> input array with elements in sorting order Step 2 -> calculate size of an array by sizeof(a)/sizeof(a[0] Step 3 -> store size in a variable say en Step 4 -> Loop For i=siz-1 ... Read More

Input number n till which prime numbers are calculated and displayed in reverse orderInput : number 30 Output : 29 23 19 17 13 11 7 5 3 2AlgorithmSTART Step 1 -> declare variables as n, I, j, flag to 0 as int Step 2 -> input number in n Step 3 -> Loop For from i to n and i>1 and i—    Step 3.1 ->. Inner loop for from j to i/2 and j>=1 and j—       Statement If %j==0 && j!=1          Set flag=0          Break       ... Read More

Input N which is equivalent to the number till where series should be printedInput : N=5 Output : 0 ¼ ½ ¾ 1AlgorithmSTART Step 1 -> declare start variables as int num , den, i, n Step 2 -> input number in n Step 3 -> Loop For from i to 0 and i End For Loop STOPExample#include int main(int argc, char const *argv[]) {    int num, den;    int i, n;    printf("Enter series limit");    scanf("%d", &n); //Till where the series will be starting from zero    for (i = 0; i < n; i++) { ... Read More

Given two sorted arrays and output should display their uncommon elementsGiven : array1[]= {1, 4, 6, 9, 12}    array2[]= {2, 4, 7, 8, 9, 10} Output : 1 2 6 7 8 10 12AlgorithmSTART Step 1 -> declare two arrays array1 and array2 with elements as int and variables n1, n2, i to 0 and j to 0 Step 2 -> calculate number of elements in array1 sizeof(array1)/sizeof(array1[0]) Step 3-> calculate number of elements in array2 sizeof(array2)/sizeof(array2[0]) Step 4 -> Loop While till i loop While i < n1 && array1[i]!=array2[j]    Print array1[i++] Step 7 -> End Loop ... Read More

It will display the missing values from the given set entered by the userGiven : array = {88, 105, 3, 2, 200, 0, 10}; Output : 1 4-9 11-87 89-99AlgorithmSTART STEP 1-> Take an array with elements, bool flag[MAX] to Fale, int i, j, n to size of array Step 2-> Loop For from I to 0 and i=0       Set flag[array[i]]=true    End IF Step 3 -> End For Loop Step 4 -> Loop For from i to 0 and i=0) {          flag[array[i]] = true; //Making the value of the elements present in ... Read More

Input three strings and replace each string with a character which user has entered and then display edited strings. After that, concatenate edited strings and display them.Input:    string 1 : tutorials replacement character for string 1 : x    String 2 : points replacement character for string 2 : y    String 3: best replacement character for string 3 : z Output :    string 1: xxxxxxxxx    String 2 :yyyyyy    String 3 : zzzz    After concatenation : xxxxxxxxxyyyyyyzzzzAlgorithmSTART Step 1-> declare three array of characters str1, str2 and str3 with variables as ch1, ch2 and ch3 ... Read More