For this, simply use update() to update. Let us create a collection with documents −> db.dem0143.insertOne({"StudentId":1, "Details":{"Name":"Chris"}}); {    "acknowledged" : true,    "insertedId" : ObjectId("5e32eb9efdf09dd6d08539b7") } > db.dem0143.insertOne({"StudentId":2, "Details":{"Name":"David"}}); {    "acknowledged" : true,    "insertedId" : ObjectId("5e32eba5fdf09dd6d08539b8") }Display all documents from a collection with the help of find() method −> db.dem0143.find();This will produce the following output −{ "_id" : ObjectId("5e32eb9efdf09dd6d08539b7"), "StudentId" : 1, "Details" : { "Name" : "Chris" } } { "_id" : ObjectId("5e32eba5fdf09dd6d08539b8"), "StudentId" : 2, "Details" : { "Name" : "David" } }Following is the query to implement $set and $push in a single update ... Read More

For this, you can use aggregate(). Let us create a collection with documents −> db.demo142.insertOne({"Value":50}); {    "acknowledged" : true,    "insertedId" : ObjectId("5e32e9c6fdf09dd6d08539b2") } > db.demo142.insertOne({"Value":45}); {    "acknowledged" : true,    "insertedId" : ObjectId("5e32e9cafdf09dd6d08539b3") } > db.demo142.insertOne({"Value":60}); {    "acknowledged" : true,    "insertedId" : ObjectId("5e32e9cdfdf09dd6d08539b4") } > db.demo142.insertOne({"Value":55}); {    "acknowledged" : true,    "insertedId" : ObjectId("5e32e9d0fdf09dd6d08539b5") } > db.demo142.insertOne({"Value":50}); {    "acknowledged" : true,    "insertedId" : ObjectId("5e32e9d9fdf09dd6d08539b6") }Display all documents from a collection with the help of find() method −> db.demo142.find();This will produce the following output −{ "_id" : ObjectId("5e32e9c6fdf09dd6d08539b2"), "Value" : 50 } { ... Read More

To find last object in collection, at first sort() to sort the values. Use limit() to get number of values i.e. if you want only the last object, then use limit(1).Let us first create a collection with documents −> db.demo141.insertOne({"Name":"Chris"}); {    "acknowledged" : true,    "insertedId" : ObjectId("5e31c347fdf09dd6d08539ae") } > db.demo141.insertOne({"Name":"David"}); {    "acknowledged" : true,    "insertedId" : ObjectId("5e31c34bfdf09dd6d08539af") } > db.demo141.insertOne({"Name":"Bob"}); {    "acknowledged" : true,    "insertedId" : ObjectId("5e31c34ffdf09dd6d08539b0") } > db.demo141.insertOne({"Name":"Mike"}); {    "acknowledged" : true,    "insertedId" : ObjectId("5e31c352fdf09dd6d08539b1") }Display all documents from a collection with the help of find() method −> db.demo141.find();This will ... Read More

For such kind of fetching, use only $nin and $in. Let us create a collection with documents −> db.demo140.insertOne({"Id":101, "Subjects":["MongoDB", "MySQL"]}); {    "acknowledged" : true,    "insertedId" : ObjectId("5e31c149fdf09dd6d08539a9") } > db.demo140.insertOne({"Id":102, "Subjects":["MongoDB", "Java"]}); {    "acknowledged" : true,    "insertedId" : ObjectId("5e31c14cfdf09dd6d08539aa") } > db.demo140.insertOne({"Id":103, "Subjects":["MongoDB", "PL/SQL"]}); {    "acknowledged" : true,    "insertedId" : ObjectId("5e31c157fdf09dd6d08539ab") } > db.demo140.insertOne({"Id":104, "Subjects":["MongoDB", "SQL Server"]}); {    "acknowledged" : true,    "insertedId" : ObjectId("5e31c163fdf09dd6d08539ac") } > db.demo140.insertOne({"Id":105, "Subjects":["C", "C++"]}); {    "acknowledged" : true,    "insertedId" : ObjectId("5e31c16ffdf09dd6d08539ad") }Display all documents from a collection with the help of find() method −> ... Read More

For this, use aggregate(). Let us create a collection with documents −>db.demo138.insertOne({"Id":101, "PlayerDetails":[{"PlayerName":"Chris", "PlayerScore":400}, {"PlayerName":"David", "PlayerScore":1000}]}); {    "acknowledged" : true,    "insertedId" : ObjectId("5e31bb9ffdf09dd6d08539a1") } >db.demo138.insertOne({"Id":102, "PlayerDetails":[{"PlayerName":"Bob", "PlayerScore":500}, {"PlayerName":"Carol", "PlayerScore":600}]}); {    "acknowledged" : true,    "insertedId" : ObjectId("5e31bbcefdf09dd6d08539a2") }Display all documents from a collection with the help of find() method −> db.demo138.find();This will produce the following output −{    "_id" : ObjectId("5e31bb9ffdf09dd6d08539a1"), "Id" : 101, "PlayerDetails" : [       { "PlayerName" : "Chris", "PlayerScore" : 400 },       { "PlayerName" : "David", "PlayerScore" : 1000 }    ] } {    "_id" : ObjectId("5e31bbcefdf09dd6d08539a2"), ... Read More

For this, use aggregate() along with $filter. Let us create a collection with documents −> db.demo137.insertOne( ...    { ...       Name1:"Chris", ...       Name2:"David", ...       Detail1:[ ...          {_id:"John", Name3:"Chris"}, ...          {_id:"Chris", Name3:"Chris"}, ...       ], ...       Detail2:[{_id:"David", Name3:"Chris"}, ...       {_id:"Carol", Name3:"Chris"}, ...       {_id:"John", Name3:"Chris"}] ...    } ... ); {    "acknowledged" : true,    "insertedId" : ObjectId("5e31b4cefdf09dd6d08539a0") }Display all documents from a collection with the help of find() method −> db.demo137.find();This will ... Read More

Let us create a collection with documents −> db.demo136.insertOne( ...    { ... ...       "Name":"Chris", ...       "Details":[ ...          { ...             "Id":"101", ...             "EmployeeName":"Mike", ...             "EmployeeDetails":[ ...             { ...                "EmpId":1001, ...                "Salary":1000 ...             }, ...             { ...         ... Read More

To update, use $set along with UPDATE. Let us create a collection with documents −>db.demo135.insertOne({"Details":[{"EmployeeId":101, "EmployeeName":"Chris", "EmployeeSalary":45000}, {"EmployeeId":102, "EmployeeName":"Chris", "EmployeeSalary":45000}]}); {    "acknowledged" : true,    "insertedId" : ObjectId("5e31a5ddfdf09dd6d085399c") }Display all documents from a collection with the help of find() method −> db.demo135.find().pretty();This will produce the following output −{    "_id" : ObjectId("5e31a5ddfdf09dd6d085399c"),    "Details" : [       {          "EmployeeId" : 101,          "EmployeeName" : "Chris",          "EmployeeSalary" : 45000       },       {          "EmployeeId" : 102,       ... Read More

To update, use update() along with $set. Let us create a collection with documents −>db.demo134.insertOne({"EmployeeId":101, "EmployeeDetails":[{"EmployeeName":"Chris", "EmployeeAge":27}, {"EmployeeName":"Bob", "EmployeeAge":28}]}); {    "acknowledged" : true,    "insertedId" : ObjectId("5e319b2f68e7f832db1a7f7c") } >db.demo134.insertOne({"EmployeeId":102, "EmployeeDetails":[{"EmployeeName":"David", "EmployeeAge":24}, {"EmployeeName":"Carol", "EmployeeAge":29}]}); {    "acknowledged" : true,    "insertedId" : ObjectId("5e319b4468e7f832db1a7f7d") }Display all documents from a collection with the help of find() method −> db.demo134.find().pretty();This will produce the following output −{    "_id" : ObjectId("5e319b2f68e7f832db1a7f7c"),    "EmployeeId" : 101,    "EmployeeDetails" : [       {          "EmployeeName" : "Chris",          "EmployeeAge" : 27       },       ... Read More

To group, use $week and $month in MongoDB. Let us create a collection with documents −> db.demo133.insertOne({"Rank":18, "DueDate":new ISODate("2020-01-10")}); {    "acknowledged" : true,    "insertedId" : ObjectId("5e31980968e7f832db1a7f78") } > db.demo133.insertOne({"Rank":12, "DueDate":new ISODate("2020-01-10")}); {    "acknowledged" : true,    "insertedId" : ObjectId("5e31982568e7f832db1a7f79") } > db.demo133.insertOne({"Rank":12, "DueDate":new ISODate("2020-02-01")}); {    "acknowledged" : true,    "insertedId" : ObjectId("5e31986568e7f832db1a7f7a") } > db.demo133.insertOne({"Rank":20, "DueDate":new ISODate("2020-02-01")}); {    "acknowledged" : true,    "insertedId" : ObjectId("5e31986c68e7f832db1a7f7b") }Display all documents from a collection with the help of find() method −> db.demo133.find();This will produce the following output −{ "_id" : ObjectId("5e31980968e7f832db1a7f78"), "Rank" : 18, "DueDate" : ISODate("2020-01-10T00:00:00Z") } ... Read More