Found 1659 Articles for Big Data Analytics

MongoDB query to select distinct and count?

AmitDiwan
Updated on 15-May-2020 06:43:20

904 Views

Let us create a collection with documents −> db.demo586.insertOne( ...    {"details": [ ...       { ...          "Name":"Chris", ...          "Marks":71 ...       }, ...       { ...          "Name":"Chris", ...          "Marks":61 ...       }, ...       { ...          "Name":"David", ...          "Marks":81 ...       } ...   ...    ] ... } ... ); {    "acknowledged" : true,    "insertedId" : ObjectId("5e9200fefd2d90c177b5bcc7") } > db.demo586.insertOne( ... Read More

MongoDB: Using reference as key and manually adding a value?

AmitDiwan
Updated on 15-May-2020 06:39:17

201 Views

To manually add value, use $push in MongoDB. Let us create a collection with documents −> db.demo585.insert({ ...    firstName: 'John', ...    lastName: 'Doe', ...    SubjectName:"MongoDB", ...    Marks: [59] ... }); WriteResult({ "nInserted" : 1 }) > db.demo585.insert({ ...    firstName: 'Chris', ...    lastName: 'Brown', ...    SubjectName:"MySQL", ...    Marks: [79] ... }); WriteResult({ "nInserted" : 1 })Display all documents from a collection with the help of find() method−> db.demo585.find();This will produce the following output −{ "_id" : ObjectId("5e91fd80fd2d90c177b5bcc3"), "firstName" : "John", "lastName" : "Doe", "SubjectName" : "MongoDB", "Marks" : [ 59 ] } { ... Read More

How to project grouping into object in MongoDB and display only the marks field?

AmitDiwan
Updated on 15-May-2020 06:36:46

74 Views

Let us first create a document −> var document= [ ...    { "SubjectName" : "MySQL", "Marks" : 78 }, ...    { "SubjectName" : "MongoDB", "Marks" : 89 }, ...    { "SubjectName" : "Java", "Marks" : 71 }, ... ];Following is the query to display document −> printjson(document);This will produce the following output −[    {       "SubjectName" : "MySQL",       "Marks" : 78    },    {       "SubjectName" : "MongoDB",       "Marks" : 89    },    {       "SubjectName" : "Java",       "Marks" : 71    } ]Following is the query to project grouping into an object in MongoDB −> var makeObject= {}; > document.forEach(function (d){ ...    makeObject[d.SubjectName] = d.Marks; ... }); > printjson(makeObject);This will produce the following output −{ "MySQL" : 78, "MongoDB" : 89, "Java" : 71 }

MongoDB query to get average in aggregation of array element?

AmitDiwan
Updated on 15-May-2020 06:29:52

824 Views

To get an average of array elements, use $avg. Let us create a collection with documents −> db.demo584.insertOne({"Marks":[75,50,85,60,80]});{    "acknowledged" : true,    "insertedId" : ObjectId("5e91d827fd2d90c177b5bcc2") }Display all documents from a collection with the help of find() method −> db.demo584.find().pretty();This will produce the following output −{    "_id" : ObjectId("5e91d827fd2d90c177b5bcc2"),    "Marks" : [       75,       50,       85,       60,       80    ] }Following is the query to find avg in the aggregation of array element −> db.demo584.aggregate([ ...    { $project: { MarksAvg: { $avg: "$Marks"} } } ... ])This will produce the following output −{ "_id" : ObjectId("5e91d827fd2d90c177b5bcc2"), "MarksAvg" : 70 }

Filter sub documents by sub document in MongoDB?

AmitDiwan
Updated on 15-May-2020 06:28:34

522 Views

For this, use aggregate() along with $unwind. Let us create a collection with documents −> db.demo583.insert([ ...    { ...       "details1" : [ ...          { ...             "details2" : [ ...                { ...                   "isMarried" : true, ...                   "Name" : "Chris" ...                }, ...                { ...         ... Read More

Apply the Group Accumulator Operator $first on the system variable $$ROOT to return reference to the root document?

AmitDiwan
Updated on 15-May-2020 06:23:46

103 Views

The accumulators are operators that maintain their state as documents progress through the pipeline.The $ROOT references the root document, i.e. the top-level document, currently being processed in the aggregation pipeline stage.Let us create a collection with documents −> db.demo582.insertOne({FirstName:"Chris", Age:21, createDate:new ISODate("2020-01-10")});{    "acknowledged" : true, "insertedId" : ObjectId("5e91ce41fd2d90c177b5bcbd") } > db.demo582.insertOne({FirstName:"Chris", Age:21, createDate:new ISODate("2020-04-21")});{    "acknowledged" : true, "insertedId" : ObjectId("5e91ce4ffd2d90c177b5bcbe") } > db.demo582.insertOne({FirstName:"Chris", Age:22, createDate:new ISODate("2020-02-11")});{    "acknowledged" : true, "insertedId" : ObjectId("5e91ce59fd2d90c177b5bcbf") } > db.demo582.insertOne({FirstName:"Chris", Age:22, createDate:new ISODate("2020-01-12")});{    "acknowledged" : true, "insertedId" : ObjectId("5e91ce6efd2d90c177b5bcc0") }Display all documents from a collection with the help of find() method ... Read More

How do I order a list and add position to its items in MongoDB?

AmitDiwan
Updated on 15-May-2020 06:19:28

243 Views

To order a list, use sort(). Let us create a collection with documents −> db.demo581.insertOne({"Name":"Chris", "Score":56});{    "acknowledged" : true, "insertedId" : ObjectId("5e91cbbbfd2d90c177b5bcb6") } > db.demo581.insertOne({"Name":"Bob", "Score":240});{    "acknowledged" : true, "insertedId" : ObjectId("5e91cbbbfd2d90c177b5bcb7") } > db.demo581.insertOne({"Name":"David", "Score":150});{    "acknowledged" : true, "insertedId" : ObjectId("5e91cbbcfd2d90c177b5bcb8") }Display all documents from a collection with the help of find() method −> db.demo581.find();This will produce the following output −{ "_id" : ObjectId("5e91cbbbfd2d90c177b5bcb6"), "Name" : "Chris", "Score" : 56 } { "_id" : ObjectId("5e91cbbbfd2d90c177b5bcb7"), "Name" : "Bob", "Score" : 240 } { "_id" : ObjectId("5e91cbbcfd2d90c177b5bcb8"), "Name" : "David", "Score" : 150 }Following is the query ... Read More

Sum unique properties in different collection elements in MongoDB and get the resultant Price?

AmitDiwan
Updated on 15-May-2020 06:17:28

330 Views

To calculate the sum of unique properties in different collection elements, use $cond along with $group. This gives the resultant price.Let us create a collection with documents −> db.demo580.insertOne( ...    { ...       "Name":"John", ...       "Id1":"110", ...       "Id2":"111", ...       "Price":10.5 ...    } ... ); {    "acknowledged" : true,    "insertedId" : ObjectId("5e918cebfd2d90c177b5bcae") } > > db.demo580.insertOne( ... { ...    "Name":"John", ...    "Id1":"111", ...    "Id2":"", ...    "Price":9.5 ... } ... ); {    "acknowledged" : true,    "insertedId" : ObjectId("5e918cecfd2d90c177b5bcaf") }Display all documents ... Read More

MongoDB query to slice only one element of array

AmitDiwan
Updated on 15-May-2020 06:12:27

280 Views

To slice only one element of array, use $slice in MongoDB. Let us create a collection with documents −> db.demo579.insertOne( ...    { ...       "_id" : 101, ...       "details" : { "FirstName" : "John" }, ...       "Marks" : [ 56,78,90,34,45,74 ] ...    } ... ); { "acknowledged" : true, "insertedId" : 101 }Display all documents from a collection with the help of find() method −> db.demo579.find().pretty();This will produce the following output −{    "_id" : 101,    "details" : {       "FirstName" : "John"    },    "Marks" : [       56,       78,       90,       34,       45,       74    ] }Following is the query to slice only one the element of the array −> db.demo579.find({},{Marks : {$slice : 1} ,"details":0,"_id":0})This will produce the following output −{ "Marks" : [ 56 ] }

Sort MongoDB Collection by Array value?

AmitDiwan
Updated on 15-May-2020 05:56:12

169 Views

To sort MongoDB collection by Array value, use aggregate() along with $sort. Let us create a collection with documents −> db.demo577.insertOne( ...    { ... ...       "student": { ...          "details": [ ...             { ...                Name:"Chris", ...                Score:45 ...             }, ...             { ...                Name:"Bob", ...                Score:33 ...   ... Read More

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