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Found 1659 Articles for Big Data Analytics
254 Views
Let’s say you have saved the Login date of users. Now, you want the users who logged in between specific dates i.e. login date. For this, use $gte and $lt operator along with count(). Let us first create a collection with documents −> db.findDataByDateDemo.insertOne({"UserName":"John", "UserLoginDate":new ISODate("2019-01-31")}); { "acknowledged" : true, "insertedId" : ObjectId("5cdd8cd7bf3115999ed511ed") } > db.findDataByDateDemo.insertOne({"UserName":"Larry", "UserLoginDate":new ISODate("2019-02-01")}); { "acknowledged" : true, "insertedId" : ObjectId("5cdd8ce7bf3115999ed511ee") } > db.findDataByDateDemo.insertOne({"UserName":"Sam", "UserLoginDate":new ISODate("2019-05-02")}); { "acknowledged" : true, "insertedId" : ObjectId("5cdd8cf3bf3115999ed511ef") } > db.findDataByDateDemo.insertOne({"UserName":"David", "UserLoginDate":new ISODate("2019-05-16")}); { "acknowledged" : true, "insertedId" : ObjectId("5cdd8d00bf3115999ed511f0") } > db.findDataByDateDemo.insertOne({"UserName":"Carol", ... Read More
273 Views
You can use $group operator with _id: null. Following is the syntax −db.yourCollectionName.aggregate([{$group: {_id:null, "anyFieldName": {$avg:"$yourFieldName"} } }]);Let us first create a collection with documents −> db.caculateTheAverageValueDemo.insertOne({"Population":100}); { "acknowledged" : true, "insertedId" : ObjectId("5cd68a197924bb85b3f4895f") } > db.caculateTheAverageValueDemo.insertOne({"Population":500}); { "acknowledged" : true, "insertedId" : ObjectId("5cd68a1c7924bb85b3f48960") } > db.caculateTheAverageValueDemo.insertOne({"Population":200}); { "acknowledged" : true, "insertedId" : ObjectId("5cd68a237924bb85b3f48961") } > db.caculateTheAverageValueDemo.insertOne({"Population":100}); { "acknowledged" : true, "insertedId" : ObjectId("5cd68a297924bb85b3f48962") } > db.caculateTheAverageValueDemo.insertOne({"Population":100}); { "acknowledged" : true, "insertedId" : ObjectId("5cd68a2e7924bb85b3f48963") }Following is the query to display all documents from a collection with the help of find() ... Read More
222 Views
Use aggregate framework along with $ifNull operator for this. The $concatArrays in aggregation is used to concatenate arrays. Let us first create a collection with documents −>db.concatenateArraysDemo.insertOne({"FirstSemesterSubjects": ["MongoDB", "MySQL", "Java"], "SecondSemesterSubjects":["C", "C++", ]}); { "acknowledged" : true, "insertedId" : ObjectId("5cd687707924bb85b3f4895c") } > db.concatenateArraysDemo.insertOne({"FirstSemesterSubjects":["C#", "Ruby", "Python"]}); { "acknowledged" : true, "insertedId" : ObjectId("5cd687927924bb85b3f4895d") } >db.concatenateArraysDemo.insertOne({"FirstSemesterSubjects":["HTML", "CSS", "Javascript"], "SecondSemesterSubjects":["CSS", "Javascript"]}); { "acknowledged" : true, "insertedId" : ObjectId("5cd687bb7924bb85b3f4895e") }Following is the query to display all documents from a collection with the help of find() method −> db.concatenateArraysDemo.find().pretty();This will produce the following output −{ "_id" : ObjectId("5cd687707924bb85b3f4895c"), ... Read More
2K+ Views
You can use $in operator to check if a value is in an array or not. Let us first create a collection with documents −> db.valueInArrayDemo.insertOne({"UserName":"John", "UserMessage":["Hi", "Hello", "Bye"]}); { "acknowledged" : true, "insertedId" : ObjectId("5cd684cf7924bb85b3f48959") } > db.valueInArrayDemo.insertOne({"UserName":"Larry", "UserMessage":["Thank You", "Amazing", "Nice"]}); { "acknowledged" : true, "insertedId" : ObjectId("5cd684d27924bb85b3f4895a") } >db.valueInArrayDemo.insertOne({"UserName":"Carol", "UserMessage":["Awesome", "Bye", "Cool"]}); { "acknowledged" : true, "insertedId" : ObjectId("5cd684d87924bb85b3f4895b") }Following is the query to display all documents from a collection with the help of find() method −> db.valueInArrayDemo.find().pretty();This will produce the following output −{ "_id" : ObjectId("5cd684cf7924bb85b3f48959"), "UserName" : "John", "UserMessage" : [ "Hi", "Hello", ... Read More
289 Views
To push elements to an existing array, use $addToSet operator along with update(). Let us first create a collection with documents −> db.pushElements.insertOne({"Comments":["Good", "Awesome", "Nice"]}); { "acknowledged" : true, "insertedId" : ObjectId("5cd682597924bb85b3f48953") }Following is the query to display all documents from a collection with the help of find() method −> db.pushElements.find().pretty();This will produce the following output −{ "_id" : ObjectId("5cd682597924bb85b3f48953"), "Comments" : [ "Good", "Awesome", "Nice" ] }Following is the query to push elements to an existing array in MongoDB −> db.pushElements.update( {_id:ObjectId("5cd682597924bb85b3f48953")}, { ... Read More
1K+ Views
For this, work with the concept of forEach(). Let us first create a collection with documents −> db.printDocuementValueDemo.insertOne({"InstructorName":"John Smith"}); { "acknowledged" : true, "insertedId" : ObjectId("5cd6804f7924bb85b3f48950") } > db.printDocuementValueDemo.insertOne({"InstructorName":"Sam Williams"}); { "acknowledged" : true, "insertedId" : ObjectId("5cd680577924bb85b3f48951") } > db.printDocuementValueDemo.insertOne({"InstructorName":"David Miller"}); { "acknowledged" : true, "insertedId" : ObjectId("5cd680637924bb85b3f48952") }Following is the query to display all documents from a collection with the help of find() method −> db.printDocuementValueDemo.find().pretty();This will produce the following output −{ "_id" : ObjectId("5cd6804f7924bb85b3f48950"), "InstructorName" : "John Smith" } { "_id" : ObjectId("5cd680577924bb85b3f48951"), "InstructorName" : "Sam Williams" } ... Read More
429 Views
For this, you need to write some code using forEach(). Let us first create a collection with documents −> db.removingWhiteSpaceDemo.insertOne({"Title":" Introduction to java "}); { "acknowledged" : true, "insertedId" : ObjectId("5cd66f387924bb85b3f4894c") }Following is the query to display all documents from a collection with the help of find() method −> db.removingWhiteSpaceDemo.find();This will produce the following output −{ "_id" : ObjectId("5cd66f387924bb85b3f4894c"), "Title" : " Introduction to java " }Following is the query to remove white spaces (leading and trailing) from string value −> db.removingWhiteSpaceDemo.find({}, {"Title": 1 }).forEach(function(myDocument) { myDocument.Title = myDocument.Title.trim(); db.removingWhiteSpaceDemo.update( { "_id": myDocument._id ... Read More
466 Views
You can use $literal operator along with aggregate framework. Let us first create a collection with documents −> db.fieldWithStaticValue.insertOne({"Name":"Larry", "Age":24}); { "acknowledged" : true, "insertedId" : ObjectId("5cd6554c7924bb85b3f48948") } > db.fieldWithStaticValue.insertOne({"Name":"Chris", "Age":23}); { "acknowledged" : true, "insertedId" : ObjectId("5cd655567924bb85b3f48949") } > db.fieldWithStaticValue.insertOne({"Name":"David", "Age":26}); { "acknowledged" : true, "insertedId" : ObjectId("5cd655607924bb85b3f4894a") }Following is the query to display all documents from a collection with the help of find() method −> db.fieldWithStaticValue.find();This will produce the following output −{ "_id" : ObjectId("5cd6554c7924bb85b3f48948"), "Name" : "Larry", "Age" : 24 } { "_id" : ObjectId("5cd655567924bb85b3f48949"), "Name" : "Chris", "Age" : 23 ... Read More
107 Views
You can use $in operator. Let us first create a collection with documents −> db.tagCountDemo.insertOne({"ListOfNames":["John", "Sam", "Carol"]}); { "acknowledged" : true, "insertedId" : ObjectId("5cd64b387924bb85b3f48944") } > db.tagCountDemo.insertOne({"ListOfNames":["Bob", "David", "John"]}); { "acknowledged" : true, "insertedId" : ObjectId("5cd64b4b7924bb85b3f48945") } > db.tagCountDemo.insertOne({"ListOfNames":["Mike", "Robert", "Chris"]}); { "acknowledged" : true, "insertedId" : ObjectId("5cd64b5d7924bb85b3f48946") } > db.tagCountDemo.insertOne({"ListOfNames":["James", "Carol", "Jace"]}); { "acknowledged" : true, "insertedId" : ObjectId("5cd64b717924bb85b3f48947") }Following is the query to display all documents from a collection with the help of find() method −> db.tagCountDemo.find().pretty();This will produce the following output −{ "_id" : ObjectId("5cd64b387924bb85b3f48944"), "ListOfNames" : ... Read More
251 Views
To sort by sub-document match, you can use aggregate framework. Let us first create a collection with documents −> db.sortBySubDocumentsDemo.insertOne( { "StudentName": "Chris", "StudentDetails": [ { "Age":21, "StudentScore":91 }, { "Age":22, "StudentScore":99 }, { "Age":21, "StudentScore":93 ... Read More