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A small indoor greenhouse (herbarium) is made entirely of glass panes (including base) held together with tape. It is \( 30 \mathrm{~cm} \) long. \( 25 \mathrm{~cm} \) wide and \( 25 \mathrm{~cm} \) high.
(i) What is the area of the glass?
(ii) How much of tape is needed for all the 12 edges?
Given:
The length of the greenhouse $l$ $=30\ cm$.
The breadth of the greenhouse $b$ $=25\ cm$.
The height of the greenhouse $h$ $=25\ cm$.
To do:
We have to find:
(i) The is the area of the glass.
(ii) The tape needed for all the 12 edges.
Solution:
The area of the glass $=2lb+2bh+2lh$
$=2{lb+bh+lh}$
This implies,
$=2{30\times25}+{25\times25}+{30\times25}$
$=2{750+625+750}$
$=(2\times2125)$
$=4250\ cm^2$
Therefore,
The area of the glass is $4250\ cm^2$.
(ii) The total length of the tape required $=$sum of the lengths of the edges of the greenhouse
$=4\times l+4\times b+4\times h$
$=4(l+b+h)$
$=4(30+25+25)$
$=320\ cm$
Therefore,
The total length of the tape required for all the 12 edges is $320\ cm$.