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A circle of radius $2\ cm$ is cut out from a square piece of an aluminium sheet of side $6\ cm$. What is the area of the left over aluminium sheet? $(Take\ \pi=3.14)$
Side of the square sheet$=6\ m$
Area of the sheet$=(Side)^2=(6)^2=36\ cm^2$
The radius of the circle$=2\ cm$
Area of the circle to be cut out$=\pi r^2$
$=\frac{22}{7}\times2\times2=\frac{88}{7}\ cm^2$
Area of the leftover sheet
$=36\ cm^2-\frac{88}{7}\ cm^2$
$=\frac{252-88}{7}\ cm^2=\frac{164}{7}\ cm^2$
$=23.44\ cm^2$
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