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A child has a die whose six faces show the letters as given below:
![](/assets/questions/media/153848-60970-1649086333.png)
The die is thrown once. What is the probability of getting
(i) A?
(ii) D?"
Given:
A die with faces ($A, B, C, D, E, A$) is thrown once.
To do:
We have to find the probability of getting
(i) $A$.
(ii) $D$
Solution:
When the die is thrown, the total possible outcomes are $A, B, C, D, E, A$
This implies,
The total number of possible outcomes $n=6$.
(i) Number of faces with letter $A=2$
Total number of favourable outcomes $=2$.
We know that,
Probability of an event $=\frac{Number\ of\ favourable\ outcomes}{Total\ number\ of\ possible\ outcomes}$
Therefore,
Probability of getting $A=\frac{2}{6}$
$=\frac{1}{3}$
The probability of getting $A$ is $\frac{1}{3}$.
(ii) Number of faces with letter $D=1$
Total number of favourable outcomes $=1$.
We know that,
Probability of an event $=\frac{Number\ of\ favourable\ outcomes}{Total\ number\ of\ possible\ outcomes}$
Therefore,
Probability of getting $D=\frac{1}{6}$
The probability of getting $D$ is $\frac{1}{6}$.