A car is accelerated on a levelled road and attains a velocity 4 times of its initial velocity. In this process the potential energy of the car
$(a)$. does not change
$(b)$. becomes twice to that of initial
$(c)$. becomes 4 times that of initial
$(d)$. becomes 16 times that of initial

Kinetic energy  $K=\frac{1}{2}mv^2$

Here, $m\rightarrow$ mass of the car

$v\rightarrow$ velocity of the car

When the velocity increased 4 times, it becomes $4v$.

Then kinetic energy $K'=\frac{1}{2}m(4v)^2$

$=16\times\frac{1}{2}mv^2$

$=16K$

Therefore, on attaining the velocity 4 times the initial velocity, the

the kinetic energy of the car becomes 16 times that of the initial.

Therefore, option $(d)$ is correct.

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Updated on: 10-Oct-2022

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