![Trending Articles on Technical and Non Technical topics](/images/trending_categories.jpeg)
Data Structure
Networking
RDBMS
Operating System
Java
MS Excel
iOS
HTML
CSS
Android
Python
C Programming
C++
C#
MongoDB
MySQL
Javascript
PHP
Physics
Chemistry
Biology
Mathematics
English
Economics
Psychology
Social Studies
Fashion Studies
Legal Studies
- Selected Reading
- UPSC IAS Exams Notes
- Developer's Best Practices
- Questions and Answers
- Effective Resume Writing
- HR Interview Questions
- Computer Glossary
- Who is Who
A 15 metres high tower casts a shadow 24 metres long at a certain time and at the same time, a telephone pole casts a shadow 16 metres long. Find the height of the telephone pole.
Given:
A 15 metres high tower casts a shadow 24 metres long at a certain time and at the same time, a telephone pole casts a shadow 16 metres long.
To do:
We have to the height of the telephone pole.
Solution:
Let $\mathrm{BC}$ be the tower and its shadow is $\mathrm{AB}$
$BC=15\ m$ and $AB= 24 \mathrm{~m}$
Let $\angle C A B= \theta$
Let $\mathrm{QR}=\mathrm{h}$ be a telephone pole and its shadow $\mathrm{PQ}=16 \mathrm{~m}$.
$\angle \mathrm{QPR}=\theta$
In $\triangle A B C$ and $\triangle PQR$,
$\angle C A B =\angle Q P R=\theta$
$\angle B =\angle Q$
Therefore, by AAA similarity,
$\triangle A B C \sim \triangle D E F$
This implies,
$\frac{BC}{QR}=\frac{AB}{PQ}$
$\frac{15}{h}=\frac{24}{16}$
$h=15\times\frac{2}{3}$
$h=10\ m$
Therefore, the height of the telephone pole is $10\ m$.