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Find the Sum of two Binary Numbers without using a method in C#?
First, declare and initialize two variables with the binary numbers.
val1 = 11010;
val2 = 10100;
Console.WriteLine("Binary one: " + val1);
Console.WriteLine("Binary two: " + val2);To get the sum, loop until both the value are 0.
while (val1 != 0 || val2 != 0) {
sum[i++] = (val1 % 10 + val2 % 10 + rem) % 2;
rem = (val1 % 10 + val2 % 10 + rem) / 2;
val1 = val1 / 10;
val2 = val2 / 10;
}Now, let us see the complete code to find the sum of two binary numbers.
Example
using System;
class Demo {
public static void Main(string[] args) {
long val1, val2;
long i = 0, rem = 0;
long[] sum = new long[30];
val1 = 11010;
val2 = 10100;
Console.WriteLine("Binary one: " + val1);
Console.WriteLine("Binary two: " + val2);
while (val1 != 0 || val2 != 0) {
sum[i++] = (val1 % 10 + val2 % 10 + rem) % 2;
rem = (val1 % 10 + val2 % 10 + rem) / 2;
val1 = val1 / 10;
val2 = val2 / 10;
}
if (rem != 0)
sum[i++] = rem;
i = i - 1;
Console.Write("Sum = ");
while (i >= 0)
Console.Write(sum[i--]);
}
}Output
Binary one: 11010 Binary two: 10100 Sum = 101110
Updated on: 22-Jun-2020
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