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C# program to split the Even and Odd integers into different arrays
Take two arrays:
int[] arr2 = new int[5]; int[] arr3 = new int[5];
Now, if the array element gets the remainder 0 on dividing by 2, it is even. Get those elements and add in another array. This loops through the length of the array:
if (arr1[i] % 2 == 0) {
arr2[j] = arr1[i];
}In the else condition, you will get the odd elements. Add them to a separate array and display them individually as shown in the below example:
Example
using System;
namespace Demo {
public class Program {
public static void Main(string[] args) {
int[] arr1 = new int[] {
77,
34,
59,
42,
99
};
int[] arr2 = new int[5];
int[] arr3 = new int[5];
int i, j = 0, k = 0;
for (i = 0; i < 5; i++) {
if (arr1[i] % 2 == 0) {
arr2[j] = arr1[i];
j++;
} else {
arr3[k] = arr1[i];
k++;
}
}
Console.WriteLine("Even numbers...");
for (i = 0; i < j; i++) {
Console.WriteLine(arr2[i]);
}
Console.WriteLine("Odd numbers...");
for (i = 0; i < k; i++) {
Console.WriteLine(arr3[i]);
}
}
}
}Output
Even numbers... 34 42 Odd numbers... 77 59 99
Updated on: 22-Jun-2020
1K+ Views
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