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C# program to find Largest, Smallest, Second Largest, Second Smallest in a List
Set the list
var val = new int[] {
99,
35,
26,
87
};Now get the largest number.
val.Max(z => z);
Smallest number
val.Min(z => z);
Second largest number
val.OrderByDescending(z => z).Skip(1).First();
Second smallest number
val.OrderBy(z => z).Skip(1).First();
The following is the code −
Example
using System;
using System.Linq;
public class Program {
public static void Main() {
var val = new int[] {
99,
35,
26,
87
};
var maxNum = val.Max(z => z);
Console.WriteLine("Maximum Number: " + maxNum);
var minNum = val.Min(z => z);
Console.WriteLine("Minimum Number: " + minNum);
var secondMax = val.OrderByDescending(z => z).Skip(1).First();
Console.WriteLine("Second Largest Number: " + secondMax);
var secondMin = val.OrderBy(z => z).Skip(1).First();
Console.WriteLine("Second Smallest Number: " + secondMin);
}
}Output
Maximum Number: 99 Minimum Number: 26 Second Largest Number: 87 Second Smallest Number: 35
Updated on: 22-Jun-2020
2K+ Views
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