8085 code to convert binary number to ASCII code

Now let us see a program of Intel 8085 Microprocessor. This program will convert binary or hexadecimal number to ASCII values.

Problem Statement

Write 8085 Assembly language program to convert binary or Hexadecimal characters to ASCII values. 

Discussion

We know that the ASCII of number 00H is 30H (48D), and ASCII of 09H is39H (57D). So all other numbers are in the range 30H to 39H. TheASCII value of 0AH is 41H (65D) and ASCII of 0FH is 46H (70D), so all other alphabets (B, C, D, E, F) are in the range 41H to 46H.

Here we are providing hexadecimal digit at memory location 8000H, The ASCII equivalent is storing at location 8001H.

The logic behind HEX to ASCII conversion is very simple. We are just checking whether the number is in range 0 – 9 or not. When the number is in that range, then the hexadecimal digit is numeric, and we are just simply adding 30H with it to get the ASCII value. When the number is not in range 0 – 9, then the number is range A – F,so for that case, we are converting the number to 41H on wards.

In the program at first we are clearing the carry flag. Then subtracting 0AHfrom the given number. If the value is numeric, then after subtraction the result will be negative, so the carry flag will beset. Now by checking the carry status we can just add 30H with the value to get ASCII value. 

In other hand when the result of subtraction is positive or 0, then we are adding 41H with the result of the subtraction.

Input

first input

second input

third input

Flow Diagram

Program

Output

first output

second output

third output

Jennifer Nicholas

Updated on: 29-Jun-2020

2K+ Views

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